e^x = 1 + x + x^2/2! + x^3/3! + … + x^n/n! for -1 < x < 1, with 0.01 percent accuracy, C program calculator

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Subject Name	C
Program Name	e^x series
Program Description	e^x = 1 + x + x^2/2! + x^3/3! + … + x^n/n! for -1 < x < 1, with 0.01 percent accuracy



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Program Code
//e^x = 1 + x + x^2/2! + x^3/3! + � + x^n/n! for -1 < x < 1, with 0.01 percent accuracy #include<stdio.h> #include<conio.h> #include<math.h> #define ACCURACY 0.0001 void main () { int i; float Term, x, Sum; printf("Enter the value of x : "); scanf("%f", &x); Sum = 1; Term = 1; for(i=1; i<=100; i++) { Term = Term * x/i; Sum = Sum + Term; if(fabs(Term) <= ACCURACY) break; } printf("\n Sum of the series = %f", Sum); printf("\n Using Library function exp(%f) = %f", x, exp(x)); getch(); }


Input Values(You must enter all user input value here, that you want to use during runtime)



To Run C Program 1. comment #include<conio.h>, clrscr(), getch(). This will not work online. This (1.) will be done automatically..., So don't worry. 2. void main() change to int main() and return 0 This (2.) will do it manually, Otherwise it give runtime error but with correct output..., So don't worry